The horizontal pipe has a cross-sectional area of 40.0 cm^2 at the wider portions and at the constriction. Water is flowing in the pipe, and the discharge from the pipe is 6.0 x 10^-3 m^3/s (6.0 L/s).(adsbygoogle = window.adsbygoogle || []).push({});

a) Find the flow speed at the wide portion.

b) Find the flow speed at the narrow portion.

c) What is the pressure difference between these portions? 1.69×104 Pa

d) What is the difference in height between the mercury columns in the U-shaped tube? 12.7 cm

How do I find a and b knowing c and d?

** So far I now:

v1A1 = v2A2

v2 = A1/A2 x v1

By applying the principle of conservation of energy:

p +(0.5*rho*v1^2) + rho*g*y1 = p + (0.5*rho*v2^2) + rho*g*y2

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# Flow speed

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