As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is L_w. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g. Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward). now i need to find the height at which the pot was dropped. im using the equation V_f^2 = v_i^2 + 2a(x_f - x_i) i figured out the final velocity to be L_w/t + g*t/2 and the initial velocity is 0 because it is dropped but when i enter that the height is (L_w/t + g*t/2) / 2*g , i get an incorrect answer. then i thought of doing the sqrt(L_w/t + g*t/2) / 2*g and it was still wrong. can someone explain what i am doing wrong?