We are studying fluid dynamics in class right now... Here is a problem that came up on my homework that im not sure how to solve: When a person inhales, air moves down the bronchus(windpipe) at 10.4 cm/s. The average flow speed of the air doubles through a constriction in the bronchus. Use (density of air) = 1.29 kg/m^3. Assuming an incompressible flow, determine the pressure drop in the constriction. Answer in units of Pa. --------------------------------- When i first looked at the problem i took "The average flow speed of the air doubles through a constriction" to mean that it goes from 10.4 cm/s to 20.8 cm/s. Then i just plugged the values into Bernoulli's equation and then plugged the following into my calculator: x + (1/2)(1.29)(.104) = (x-y) + (1/2)(1.29)(.208).... only solving for y, which would be the pressure drop. i got .020929 Pa as my answer, and this is not correct. So, unless i made some mistake in the above equations, i assume that "The average flow speed of the air doubles through a constriction" means something else... but im not sure where to start. Any help is appreciated.