# Fluid dynamics.

1. Jan 14, 2010

### victorlee2

1. The problem statement, all variables and given/known data
The horizontal constricted pipe illustrated in
lee (vl3765) – UTHW#34-Dluid Dynamics1 – hamaguchi – (32001) 3
the figure (a Venturi tube), can be used to
measure flow velocities in an incompressible
fluid.
The ratio for the cross section areas of the
tube is A2/A1 = 0.478, the difference in the
pressures is P1 −P2 = dP = 18.2 Pa , and the
density of the fluid is 1.08 kg/m3.
Find the speed of the fluid near the right
hand end of the tube (i.e., find v2).

2. Relevant equations
Bernoulli's equation

3. The attempt at a solution
alright so i wrote out the bernoulli's equation P1 + 1/2rov1^2 + rogh1 = P2 + 1/2rov2^2 + rogh2

so they told us that P1-_2 = 18.2 so i moved P2 to the other side, thus making it 18.2. then since A2/A1 = .478 that means v1/v2 = .478 as well. doing that i found out that v1 = v2*.478. so i just plugged all these founds into the equation. also since height is = 0m, both sides with the h's are crossed out leaving P1 + 1/2 rov1^2 = P2 + 1/2rov2^2. i cannot get the answer and this homework is due in 1/2 an hr. ive been working on this for 4 hours straight no joke. PLEASE HELP

2. Jan 14, 2010

forget it.