(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The horizontal constricted pipe illustrated in

lee (vl3765) – UTHW#34-Dluid Dynamics1 – hamaguchi – (32001) 3

the figure (a Venturi tube), can be used to

measure flow velocities in an incompressible

fluid.

The ratio for the cross section areas of the

tube is A2/A1 = 0.478, the difference in the

pressures is P1 −P2 = dP = 18.2 Pa , and the

density of the fluid is 1.08 kg/m3.

Find the speed of the fluid near the right

hand end of the tube (i.e., find v2).

2. Relevant equations

Bernoulli's equation

3. The attempt at a solution

alright so i wrote out the bernoulli's equation P1 + 1/2rov1^2 + rogh1 = P2 + 1/2rov2^2 + rogh2

so they told us that P1-_2 = 18.2 so i moved P2 to the other side, thus making it 18.2. then since A2/A1 = .478 that means v1/v2 = .478 as well. doing that i found out that v1 = v2*.478. so i just plugged all these founds into the equation. also since height is = 0m, both sides with the h's are crossed out leaving P1 + 1/2 rov1^2 = P2 + 1/2rov2^2. i cannot get the answer and this homework is due in 1/2 an hr. ive been working on this for 4 hours straight no joke. PLEASE HELP

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# Homework Help: Fluid dynamics.

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