- #1
RazerM
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I am currently doing revision for an upcoming exam and can't work out how this particular question is solved. Attached is an image of the system.
A pump draws water from a large tank and delivers it to atmosphere through a 50 mm diameter nozzle at a level 10 m above the free water surface in the tank. The pressure rise across the pump (the pipes entering and leaving the pump have the same diameter) is measured as 136 [itex]\textrm{kN}/\textrm{m}^{2}[/itex].
Calculate the volume flowrate through the system and the power in the discharge jet. Ignore energy losses in the pump, pipeline and nozzle.
Answers given; [itex]q=0.0171\,\textrm{m}^{3}/\textrm{s}[/itex]
[itex]W=645\,\textrm{W}[/itex]
[tex]\begin{align}
A&=\frac{\pi}{4}D^{2}\\
q&=Av\\
\textrm{Power} &= \rho q\cdot W_{\textrm{in}}
\end{align}[/tex]
I am choosing two points to apply bernoulli's equation; the reservoir surface and the point where fluid leaves the nozzle.
[tex]
\begin{align*}P_{1}&=0\,(\textrm{Gauge Pressure})\\
P_{2}&=136\textrm{kN}/\textrm{m}^{2}\\
v_{1}&=0\\
v_{2}&=?
\end{align*}[/tex]
Now the equation from what I understand:
[tex]\begin{align*}
\frac{P_{1}}{\rho}+\frac{v_{1}^{2}}{2}+gZ_{1}+W_{\textrm{in}}&=\frac{P_{2}}{\rho}+\frac{v_{2}^{2}}{2}+gZ_{2}+\textrm{losses}\\
W_{\textrm{in}} &= \frac{P_{2}}{\rho}+\frac{v_{2}^{2}}{2}+gZ_{2}
\end{align*}[/tex]
Using the given answers for q gives the incorrect Power from equation (3) which means I am misunderstanding where to take values from in the system or how to implement the pump pressure change into the equations.
Any help is appreciated.
Homework Statement
A pump draws water from a large tank and delivers it to atmosphere through a 50 mm diameter nozzle at a level 10 m above the free water surface in the tank. The pressure rise across the pump (the pipes entering and leaving the pump have the same diameter) is measured as 136 [itex]\textrm{kN}/\textrm{m}^{2}[/itex].
Calculate the volume flowrate through the system and the power in the discharge jet. Ignore energy losses in the pump, pipeline and nozzle.
Answers given; [itex]q=0.0171\,\textrm{m}^{3}/\textrm{s}[/itex]
[itex]W=645\,\textrm{W}[/itex]
Homework Equations
[tex]\begin{align}
A&=\frac{\pi}{4}D^{2}\\
q&=Av\\
\textrm{Power} &= \rho q\cdot W_{\textrm{in}}
\end{align}[/tex]
The Attempt at a Solution
I am choosing two points to apply bernoulli's equation; the reservoir surface and the point where fluid leaves the nozzle.
[tex]
\begin{align*}P_{1}&=0\,(\textrm{Gauge Pressure})\\
P_{2}&=136\textrm{kN}/\textrm{m}^{2}\\
v_{1}&=0\\
v_{2}&=?
\end{align*}[/tex]
Now the equation from what I understand:
[tex]\begin{align*}
\frac{P_{1}}{\rho}+\frac{v_{1}^{2}}{2}+gZ_{1}+W_{\textrm{in}}&=\frac{P_{2}}{\rho}+\frac{v_{2}^{2}}{2}+gZ_{2}+\textrm{losses}\\
W_{\textrm{in}} &= \frac{P_{2}}{\rho}+\frac{v_{2}^{2}}{2}+gZ_{2}
\end{align*}[/tex]
Using the given answers for q gives the incorrect Power from equation (3) which means I am misunderstanding where to take values from in the system or how to implement the pump pressure change into the equations.
Any help is appreciated.