An air bubble originating from a deep-sea diver has a radius of 1.8 mm at the depth of the diver. When the bubble reaches the surface of the water, it has a radius of 2.6 mm. Assume that the temperature of the air in the bubble remains constant. The acceleration of gravity is 9.81 m/s^2. A) Determine the depth of the diver. Answer in units of m. B) Determine the absolute pressure at this depth. Answer in units of Pa. P=rho(density) Pair=1.29 kg/m^3 Psea water=1025 kg/m^3 The volume of a sphere = (4/3)(Pi)(r^3) Any help with this would be greatly appreciated.