A pipe is designed to have its cross sectional area decreasing linearly from 12-inch diameter to 6-inch diameter. What is the acceleration rate at a section 10 inches from the ending section of 12-inch pipe at time = 3 sec? The volume flow rate Q=2t cfs (note: t is in sec). Also given is the length of pipe from the 12-inch diameter to the 6-inch diameter is 30-inches.
Might use ax = du/dt
The Attempt at a Solution
Tried solving Q by letting t=3 and substituting into the Q equation to get 6 cfs, but it hasn't led me any where.