Solving Hydraulic Lift & Friction Force Problems

In summary, the first conversation discusses the hydraulic lift and how a force △F is needed to raise the larger piston by a distance d2. The second conversation is about a horizontal pipe passing through a wall under water and finding the frictional force between the plug and the wall. The volume of the lake is assumed to be large enough that its surface remains constant.
  • #1
ascll
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Homework Statement



1)

Consider the hydraulic lift which has a smaller piston of area A1 and a larger piston area A2. Initially the two pistons are not moving.

Show that in order to raise the larger piston by a distance d2, it is necessary to apply a force △F = ρg(A1 + A2)d2 on a smaller piston
2)

The water in the lake behind a wall is 15 m deep. A horizontal pipe 4 cm in diameter passes through the wall 6 m below the water surface, which is blocked by a plug. Assume the volume of lake is so large that its surface remains constant even when water flows out of the wall.
Find the frictional force between the plug and the wall.

The Attempt at a Solution



1) for this question , i can only think about the relation of the area , force and distance , but i cannot group them up and form the equation as the question stated

F1 * d1 = F2 * d2
A1 * F2 = A2 * F1

2) i don't know where the friction come from and seems don't know what's going on in this question...
 
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  • #2
nobody can help...?
 
  • #3
For the first question, is there a picture given? Can you describe the picture?

For the second question... I don't understand this part: "Assume the volume of lake is so large that its surface remains constant" surface area?
 

What is a hydraulic lift and how does it work?

A hydraulic lift is a machine that uses pressurized fluid to lift heavy objects. It works by using a pump to push fluid into a small cylinder, which then pushes a larger cylinder up, lifting the object. The force of the lift is multiplied by the ratio of the sizes of the two cylinders.

What factors affect the amount of force needed to lift an object with a hydraulic lift?

The amount of force needed to lift an object with a hydraulic lift depends on the weight of the object, the size of the cylinders, and the pressure of the fluid being used. Friction also plays a role and can require additional force to overcome.

How do you calculate the amount of force needed to overcome friction in a hydraulic lift?

To calculate the force needed to overcome friction in a hydraulic lift, you need to know the coefficient of friction between the surfaces, the normal force of the object on the surface, and the angle of incline (if applicable). You can then use the formula F = μNcosθ, where F is the force needed to overcome friction, μ is the coefficient of friction, N is the normal force, and θ is the angle of incline.

What are some common sources of error when solving hydraulic lift and friction force problems?

Some common sources of error when solving hydraulic lift and friction force problems include incorrect units, rounding errors, and not taking into account all the forces acting on the object. It is important to carefully label and convert all units and to double check all calculations to reduce the chances of errors.

How can I improve the efficiency of a hydraulic lift?

To improve the efficiency of a hydraulic lift, you can use a fluid with a higher pressure or increase the size of the cylinders. Reducing friction by lubricating the moving parts and minimizing the weight of the object being lifted can also improve efficiency. Additionally, regular maintenance and proper calibration of the lift can help ensure optimal performance.

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