Fluid Mechanics: Bernoullis Theorem Demonstration?

  1. Having trouble using the bernoulli equation to work out the dynamic head for this experiment.

    the equation I am using is as follows:

    P1/ρg+(v1^2)/2g+z1=P2/ρg+(v2^2)/2g+z2

    Where:

    P= static pressure
    v = fluid velocity
    z = vertical elevation of fluid so z1 = z2 for horizontal tube

    so equation is now:

    P1/ρg+(v1^2)/2g=P2/ρg+(v2^2)/2g

    now the measurements taken for static presure head (h), in meter which is related to P using this realtionship:

    h = P/ρg

    which allows the bernoulli equation to be rewritten as:

    h1+(v1^2)/2g=h2+(v2^2)/2g

    now i am having trouble rearanging this part of the equation to work out the the dynamic head for the experiment
     
  2. jcsd
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