I've attached the problem
I'm kind of lost as to how to even start this problem.
For part )
I think my first approach is to sum up forces in the vertical direction.
Which would yield F-W1-W2=ma=0
W1=weight of submerged volume of oak
W2=weight of the steel thing.
W1=(Specific weight of oak)*(L-h)*A
(L-h)*A is essentially the volume of the submerged oak or the volume of the displaced fluid.
Can someone verify if this is the right approach?
Also, how do I find the specific weight of oak & steel given the specific gravity?
51.1 KB Views: 317