- #1

pyroknife

- 613

- 3

## Homework Statement

I've attached the problem

I'm kind of lost as to how to even start this problem.

For part )

I think my first approach is to sum up forces in the vertical direction.

Which would yield F-W1-W2=ma=0

Where:

F=buoyancy force

W1=weight of submerged volume of oak

W2=weight of the steel thing.

W1=(Specific weight of oak)*(L-h)*A

(L-h)*A is essentially the volume of the submerged oak or the volume of the displaced fluid.

Can someone verify if this is the right approach?

Also, how do I find the specific weight of oak & steel given the specific gravity?