Fluid mechanics faucet problem

  • Thread starter parttime
  • Start date
  • #1
13
0
a stream of water in steady flow from a kitchen faucet. at the faucet the diameter of the stream is .96cm teh stream fill a 125cm^3 conaienr in 16.3s find teh diamiter if the stream 13cm below he opening if the faucet
i know that A1V1 = A2V2 = constant so pi *.49^2 *V1= pi r^2 *V2
how do i get the velocitys from (125cm^3 in 16.3s) to me that is the average v??
 

Answers and Replies

  • #2
Tide
Science Advisor
Homework Helper
3,076
0
HINT:

[tex]\rho A v[/tex]

is the volume of liquid that passes through a given area per unit time.
 
  • #3
13
0
this is what i do and still dont get the right answer
solve for v with pAv =125cm^3/16.3s with p= density of water A= area of stream at the faucet so v = v1
with v1 i solve for v2 with v2^2 = v1+ 2 a (xf- xi)
having both velocitys i use A1v1=A2v2 and A2=pi * r^2 i to solve for r
i also change r1 to .0048m delta x to -.13m a=-9.8 when solving for v and vf where am i going wrong??
 

Related Threads on Fluid mechanics faucet problem

  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
1
Views
720
  • Last Post
Replies
13
Views
4K
  • Last Post
Replies
1
Views
898
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
13
Views
3K
  • Last Post
Replies
10
Views
496
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
6
Views
2K
Top