- #1

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i know that A1V1 = A2V2 = constant so pi *.49^2 *V1= pi r^2 *V2

how do i get the velocitys from (125cm^3 in 16.3s) to me that is the average v??

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- #1

- 13

- 0

i know that A1V1 = A2V2 = constant so pi *.49^2 *V1= pi r^2 *V2

how do i get the velocitys from (125cm^3 in 16.3s) to me that is the average v??

- #2

Tide

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HINT:

[tex]\rho A v[/tex]

is the volume of liquid that passes through a given area per unit time.

[tex]\rho A v[/tex]

is the volume of liquid that passes through a given area per unit time.

- #3

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solve for v with pAv =125cm^3/16.3s with p= density of water A= area of stream at the faucet so v = v1

with v1 i solve for v2 with v2^2 = v1+ 2 a (xf- xi)

having both velocitys i use A1v1=A2v2 and A2=pi * r^2 i to solve for r

i also change r1 to .0048m delta x to -.13m a=-9.8 when solving for v and vf where am i going wrong??

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