- #1

gikwiye

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## Homework Statement

a vertical, 1cm-diameter jet of water impinges upon a bathroom scale such that the latter exhibits a reading of 5 kg. Estimate the volume flow rate of the jet.

## Homework Equations

p=F/A

Q(volume flow rate)=U*A(area where the jet of water is applied on)

a=pi*r²

F=mg

P=(rho*U²)/2 (if we consider that the pressure applied on the scale by the jet is essentially dynamic pressure) (don't know if this is correct though)

## The Attempt at a Solution

let's calculate A first

A=2.5x10^(-5)*pi

then let's change the kg into Newtons:

F=5*9.81=49.05N

P is F/A therefore: P=49.05/(2.5*10^(-5))=624.523kpa

with P=(rho*U²)/2 if find U=35.341m/s

and with

Q(volume flow rate)=U*A(area where the jet of water is applied on)

I find Q=2.7756 l/s

just wanna know if I should include the atmospheric pressure or not

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