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Calculating Pressure Change in a Manometer Due to Removal of Air Bubble
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[QUOTE="ramilla, post: 4487821, member: 486575"] [h2]Homework Statement [/h2] a manometer consisting of tube that is 1.25 cm inner diameter . on one side , the manometer leg contains mercury,10cc of an oil(S.G.=1.4)and 3 cc of air as a bubble in oil . the other leg contains only mercury . both legs are open to atmosphere and static . An accident occurs in which 3cc of oil and air bubble are removed from one leg . how much do mercury height levels change? [h2]Homework Equations[/h2] Δp=ρgh [h2]The Attempt at a Solution[/h2] i calculated the change in pressure due to 3 cc air bubble ∏/4 * 1.25*1.25*l=3 where l = length of airbubble column l=2.445 cm ...after that cudnt proceed please help me how to do it asap [/QUOTE]
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Calculating Pressure Change in a Manometer Due to Removal of Air Bubble
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