# Fluid Mechanics Piston Problem

1. Nov 29, 2013

### Calculuslover9

1. The problem statement, all variables and given/known data
A hydraulic car lift has a reservoir of fluid connected to two cylindrical fluid filled pipes. The pipe directly below the car has a diameter of 1.8 m. the pipe o which the plunger acts has a diameter of 0.045m. the plunger is depressed a distance of 1.5m. How much does the car rise?
http://tinypic.com/r/wam5xd/5
http://tinypic.com/r/wam5xd/5
2. Relevant equations

Ain X ΔXin=Aout X Δout

3. The attempt at a solution
Since the piston movess downaward thorugh a displacement Δx1 equals the volume of liquid pushed up on the right as the right piston moves upward through a displacement

http://tinypic.com/r/2pr8wvt/5

If the image did not show please look at below or look at link

http://tinypic.com/r/2pr8wvt/5

(π (〖0.0225〗^2 m)/4m)(1.5m)=(π (〖0.9〗^2 m)/1.5m)(x)
x=0.00094m

My attempt was wrong. But I am not sure why, any hints to what I can do?

Last edited: Nov 29, 2013
2. Nov 29, 2013

### rock.freak667

The work done by Force F1 should be the same as the work done by the force F2 such that

F1x1 = F2x2

From this you can find the ratio of F2/F1 and thus get x2

3. Nov 29, 2013

### Calculuslover9

I understand your thought processes, however, no mass is given so how, can I use that equation?

4. Nov 29, 2013

### Calculuslover9

I understand your thought processes, however, no mass is given so how, can I use that equation?

5. Nov 29, 2013

### nil1996

The change in volume of fluid in one piston is equal to the change in volume of the other.