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Fluid Mechanics Piston Problem

  1. Nov 29, 2013 #1
    1. The problem statement, all variables and given/known data
    A hydraulic car lift has a reservoir of fluid connected to two cylindrical fluid filled pipes. The pipe directly below the car has a diameter of 1.8 m. the pipe o which the plunger acts has a diameter of 0.045m. the plunger is depressed a distance of 1.5m. How much does the car rise?
    http://tinypic.com/r/wam5xd/5
    If image wont show please look at link
    http://tinypic.com/r/wam5xd/5
    2. Relevant equations

    Ain X ΔXin=Aout X Δout



    3. The attempt at a solution
    Since the piston movess downaward thorugh a displacement Δx1 equals the volume of liquid pushed up on the right as the right piston moves upward through a displacement


    http://tinypic.com/r/2pr8wvt/5

    If the image did not show please look at below or look at link

    http://tinypic.com/r/2pr8wvt/5

    (π (〖0.0225〗^2 m)/4m)(1.5m)=(π (〖0.9〗^2 m)/1.5m)(x)
    x=0.00094m

    My attempt was wrong. But I am not sure why, any hints to what I can do?
     
    Last edited: Nov 29, 2013
  2. jcsd
  3. Nov 29, 2013 #2

    rock.freak667

    User Avatar
    Homework Helper

    The work done by Force F1 should be the same as the work done by the force F2 such that

    F1x1 = F2x2

    From this you can find the ratio of F2/F1 and thus get x2
     
  4. Nov 29, 2013 #3
    I understand your thought processes, however, no mass is given so how, can I use that equation?
     
  5. Nov 29, 2013 #4
    I understand your thought processes, however, no mass is given so how, can I use that equation?
     
  6. Nov 29, 2013 #5
    The change in volume of fluid in one piston is equal to the change in volume of the other.
     
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