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The correct answer to this problem is h2 = h1 but I don't get it. According to what I understand,

F=p/A

So for the Tube on the left:

F1 = P/A = ([itex]\rho[/itex]*g*h1)/A1

For tube on the right:

F1 = P/A = ([itex]\rho[/itex]*g*h1)/3*A1

I get h2=3h1 (i know if you think about it this does not make sense, but i don't what i am not getting).

F=p/A

So for the Tube on the left:

F1 = P/A = ([itex]\rho[/itex]*g*h1)/A1

For tube on the right:

F1 = P/A = ([itex]\rho[/itex]*g*h1)/3*A1

I get h2=3h1 (i know if you think about it this does not make sense, but i don't what i am not getting).