There is a question that I have been stumped on for a while now.(adsbygoogle = window.adsbygoogle || []).push({});

it is as follows:

"The left arm of a tube has a corss sectional area A1 of 10.0cm^2 and the right arm has a cross sectional area of A2 = 5.00cm^2.

100g water are poured into the right arm.

b) givent he density of mercury is 13.6g/cm^3, what distance 'h' does the mercury rise in the left arm?

I worked out in question 'a' that the length of the column of water is 20cm.

With this, I used Pnot + densityofmercury*g*Hmercury = Pnot + densityofwater*g*Hwater

This gives me the Hmercury displaced on the right arm.

With that displacement, which I calculated to be Hmercury = 1.47cm, I can calculate the displacement on the left side.

V1=A1H1 <volume of displacement1\____should be equal

V2=A2Hmercury <volume of displacement2/

V1 = V2

therefore A2(1.47cm)/A1 = H1

I calculated H1 to be 0.735cm or 7.3mm

However, this answer is wrong. THe correct answer is 4.9mm

Why is this?? I am truly frustrated and stumped:grumpy:

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# Homework Help: Fluid mechanics question

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