Im trying to complete homework for my physics class but i can't figure this problem out. here's the problem: The axis of a cylindrical container is vertical. The container is filled with equal masses of water and oil. The oil floats on top of the water, and the open surface of the oil is at a height h above the bottom of the container. What is the height, h, if the pressure at the bottom of the water is 9.6 kPa greater than the pressure at the top of the oil? Assume the oil density is 875 kg/m3. density of water i assume to be 1000 kg/m3. The help for this problem said to assume that the masses of the two liquids are the same mass, and use this obtain a relationship between the two fluids for a height. So F = mg = p(density)*A*dh*g p(water)*dh*g = p(oil)*dh*g area(A) would cancel because it is the same then i figured we would have to use the equation P(pressure)=P0(pressure at the top) + p*g*(dh) From there im assuming that P-P0 = 9.6kPa so 9.6kPa = p(water)*dh*g + p(oil)*dh*g then converted 9.6kPa to 9600 Pa, and solved for dh, but im getting the wrong answer. Can anyone help me out, show me what im doing wrong. Any help would be greatly appreciated.