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**1. Homework Statement**

A car lift has two pistons. The one that lifts the car has an area of 2 meters squared, the one that is pushed down has an area of 1 meter squared. If a car weighing 2000kg is to be lifted 2m, how far must the smaller piston be pushed down? The pistons are of negligible mass.

**2. Homework Equations**

F1/A1 = F2/A2

**3. The Attempt at a Solution**

So:

(2000)(9.81)(2) / 2 = mgh or (9.81)mh

I'm getting stuck where I find the height on the other side. Since the pistons were of negligible mass I thought that meant that it would just be equal to 9.81h and then divided by 9.81 to solve for h. Is this the correct approach or am I missing something?