Hi I have a midterm study guide question. This one has stumped me for a while and probably the only one undone. 1. The problem statement, all variables and given/known data Suppose there is a semi-circular plate of radius 5 ft that rests on its diameter and is tilted at 45 degree angle to the bottom of a tank lled with water to depth 6 feet. Find the force exerted by the water against one side of the plate. (The weight-density of water is 62.4 lb=ft^3) 2. Relevant equations So I'm reading the book and I know that to solve the problem Force is weight-density of water (62.4) times the depth (6-y) and the area. Now the problem is I'm not quite sure how to approach the area. I just can't seem to grasp the image of the tank. Not to mention the 45 degree angle really confused my approach. I was under the assumption that its a 6ft tall cylinder with length 10ft and a plate on the bottom tilted at 45 degrees 3. The attempt at a solution Problem seems simple, but I can't seem to figure out the 45 degree plate to find the area. What i have is: Integral from 0 to 6 of (62.4)(6-y)(area) Now this is assuming that I approached this correctly.