Hi I have a midterm study guide question. This one has stumped me for a while and probably the only one undone.(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

Suppose there is a semi-circular plate of radius 5 ft that rests on its

diameter and is tilted at 45 degree angle to the bottom of a tank lled with water to depth

6 feet. Find the force exerted by the water against one side of the plate. (The

weight-density of water is 62.4 lb=ft^3)

2. Relevant equations

So I'm reading the book and I know that to solve the problem Force is weight-density of water (62.4) times the depth (6-y) and the area.

Now the problem is I'm not quite sure how to approach the area. I just can't seem to grasp the image of the tank. Not to mention the 45 degree angle really confused my approach. I was under the assumption that its a 6ft tall cylinder with length 10ft and a plate on the bottom tilted at 45 degrees

3. The attempt at a solution

Problem seems simple, but I can't seem to figure out the 45 degree plate to find the area.

What i have is:

Integral from 0 to 6 of (62.4)(6-y)(area)

Now this is assuming that I approached this correctly.

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# Fluid Pressure problem

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