1. The problem statement, all variables and given/known data 2. Relevant equations P1= Patm + ρwatervg P2= Patm + ρmer.vg 3. The attempt at a solution so both sides of the tubes are open to atmosphere pressure and are in equilibrium. I can get P1 =P2 the 1 atm from each side cancels out. g (gravity) cancels out I'm left with volume (or distance in this case) of water times density of water = distance of mercury times density of mercury: (1000 kg/m3 ) (0.12m) = distance of mercury ( 13600 kg/m3) solving for distance of mercury gives 0.088m or 0.88 cm is this correct?