Fluid statistics

  • Thread starter Nhlaka
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  • #1
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Homework Statement


A u-shaped tube open to air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of the tube until the vertical height of water is 15 cm.


Homework Equations


(a)What is the gauge pressure at the water-mercury interface?[ans 1.47*10^3Pa]

(b)calculate the vertical distance h from the top of the mercury in the right-hand arm of the tube to the top of the water in the left-arm.[ans 13.9 cm]


The Attempt at a Solution


(a) p=p_0 +rho*g*h
p = 0 + 13.6*10^3 *9.8*0.15
p= 1.99*10^4
(b) 13-1.47=13.5
 
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Answers and Replies

  • #2
Doc Al
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(a) p=p_0 +rho*g*h
p = 0 + 13.6*10^3 *9.8*0.15
p= 1.99*10^4
Check your value for the density of water.
 
  • #3
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The answers are already given in brackets so my problem is deriving them:confused:
 
  • #4
Doc Al
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The answers are already given in brackets so my problem is deriving them:confused:
You gave an attempted solution and I stated why it was wrong. Did you look up the density of water?
 
  • #5
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Thanks a million realy appreaciate:smile:
 
  • #6
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How do i then tickle (b) im totally clueless on that
 
  • #7
Doc Al
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How do i then tickle (b) im totally clueless on that
Draw a picture. Hint: At the same vertical position (height), the pressure must be the same. Imagine a horizontal line that intersects the mercury/water boundary.
 
  • #8
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Thank you very much Pf mentor i got the solution to the question:smile::smile:
 
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