In a hydraulic lift, the radii of the pistons are 2.50 cm and 10 cm. A car of mass 1000 kg is to be lifted for inspection.
b) what force must be applied to the proper piston to be able to lift the car with ease?
C) If the smaller piston is pushed by 10 cm, how far is the car lifted?
P2 = P1 + pgd
P = F/A
The Attempt at a Solution
I found that in b, the required force is 612.5 N, however for C I just don't know what to do. I try putting in 10 cm into the first formula (converting 10 cm into 0.1 m), however I just don't know what to do from there.