Fluids at rest problem help!!!!!! 1. The problem statement, all variables and given/known data How much force does it take to hold 0.5 m^3 of medium density (specific gravity = 0.77) wood under water? 3. The attempt at a solution density of wood is 770 kg/m^3. Fb is the force of buoyancy that pushes the wood up. F-Fb = mg F-9.81(0.5)(1000) = 770*0.5 (9.81) F = 8682 N I don't know what the answer is, but i don't think that this is right. It might be i don't know. Could someone help.