1. The problem statement, all variables and given/known data The plastic tube has a cross-sectional area of 5.00 cm². The tube is filled with water until the short arm (of length d = 0.800 m) is full. Then the short arm is sealed and more water is gradually poured into the long arm. If the seal will pop off when the force on it exceds 9.80 N, what total height of the water in the long arm will put the seal on the verge of popping? 2. Relevant equations P = Po + pgh P = F / A 3. The attempt at a solution Well I know that at their equal height, their pressure is in equilibrium (equal at that point). H = h + d Fpo = 9.80 N (From free body diagram): F2 - F1 = Fpo PtA - PoA = Fpo Pt = Po + pgh This is where I'm stuck. I don't know what to do from here. Maybe i'm doing it completely wrong or there's an easier way. Can someone please help!