- #1

lovelylm1980

- 18

- 0

This is how I figure the problem should be solved:

Q= pi*r^4(p1-p2)/8L*viscosity

Area= 6e-4m^2

h= 0.6m

P= rho*g*h= 1.00e3kg/m^3*9.8m/s^2*0.6m= 5880N/m^2

what I can't figure out is how do I get viscosity from the area

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- Thread starter lovelylm1980
- Start date

- #1

lovelylm1980

- 18

- 0

This is how I figure the problem should be solved:

Q= pi*r^4(p1-p2)/8L*viscosity

Area= 6e-4m^2

h= 0.6m

P= rho*g*h= 1.00e3kg/m^3*9.8m/s^2*0.6m= 5880N/m^2

what I can't figure out is how do I get viscosity from the area

- #2

HallsofIvy

Science Advisor

Homework Helper

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- 971

You CAN'T get "viscosity" from area. Viscosity is a phyical property of the fluid itself. If you really needed it you should look up the viscosity is a table of physical/chemical constants.

However, I don't think that formula is what you want. The point of saying that this tank is "of very large area" is that as water drains the height of the water above the hole stays essentially the same. I would suggest treating the water above the hole as a solid falling under gravity. How much water will pass through the hole in unit time?

- #3

lovelylm1980

- 18

- 0

so do I use the formula Q=volume/time?

- #4

Doc Al

Mentor

- 45,461

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I believe I answered this question in the other forum. Look it up.

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