# Fluids Pressure Question

1. Mar 21, 2017

### joshmccraney

Suppose we have a pipe of some length $2L$ and at the ends there is to spherical caps of fluid, as shown in the attachment. Is it possible for the two ends to have different curvatures in equilibrium?

My initial thoughts are no, since pressure is proportionate to curvature (Young-Laplace) and I don't think a pressure gradient would exist in equilibrium. What do you think?

#### Attached Files:

• ###### Screen Shot 2017-03-21 at 1.57.34 AM.png
File size:
28.6 KB
Views:
77
2. Mar 21, 2017

### John Morrell

You can have a pressure gradient in equilibrium. You just need some other force acting to balance out the force from pressure. For example, water at the bottom of a pool is at much higher pressure than water at the top of a pool. Air pressure is much higher on the surface of the earth than 2 miles above the surface. If your pipe is held vertically, than you would by necessity have a pressure gradient which would be equal to the density times earth gravity times the depth.

Furthermore, you could have different atmospheric pressures applied to the different ends, though that might be reading way too much into it.

3. Mar 21, 2017

### joshmccraney

Hmmm yea that makes a lot of sense. So in the absence of gravity and assuming atmospheric pressure to be constant, for equilibrium to exist the curvatures would have to be constant at both ends?

4. Mar 21, 2017

### John Morrell

Assuming no other forces on the fluid in the pipe, than we'd have to assume zero pressure gradient and thus equal curvatures.

5. Mar 21, 2017

### joshmccraney

Thanks!

6. Mar 21, 2017

### John Morrell

This just comes down to a definition of equilibrium. We're assuming all forces in the fluid are canceling each other out, so that the net force is zero. Pressure gradients indicate a force, so for a pressure gradient to exist the fluid either has to have some other force at work, or it has to not be in equilibrium.