Fluids problem

  • Thread starter kitty9035
  • Start date
  • #1
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Homework Statement


Water is flowing at 1 m/s in a circular pipe. If the diameter of the pipe decreases to four-ninth its former value, what is the velocity fo the water downstream?


Homework Equations



AV=AV

3. The Attempt at a Solution [/b
(Area1)(Velocity1)=(Area2)(Velocity2)
then...
(A1)(1 m/s)=(4/9)A1(V2) ?
or
A1=(4/9)(V2)

Is that right what would u do next??
 

Answers and Replies

  • #2
148
0
Rewrite the area in terms of its diameter, and then try again.
 
  • #3
104
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Indeed, remember the area for a circle? *circular* being the key word =).
 
  • #4
118
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couldn't you just with what your given calculate the volumetric flow rate then, then apply Q = AV to get the velocity in the second pipe.. thats how I would do it
 
  • #5
104
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A1V1 = A2V2, since the density is uniform/incompressible.

You could do as you say, but then you'd have the equation:
A1 * (delta L1) / delta t = A2 * (delta L2) / delta t

A1V1 = A2V2 is a better one to use; well more "simple" one.
 

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