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## Homework Statement

A cylindrical can of height h and base area A is immersed in water to a depth ho and left to sink down. A small hole of area 'a' exists at the bottom of the base of the can. Determine how quickly the can sinks.

http://img80.imageshack.us/my.php?image=fluids1wb7.jpg

## Homework Equations

http://img178.imageshack.us/my.php?image=fluidssolmz5.jpg

Thus, vo = sqrt(2gy)

AV = avo

V: velocity of fluid w.r.t. the container

## The Attempt at a Solution

Thus,

dy/dt = (a/A)sqrt(2gy)

or, dy/sqrt(y) = (a/A) sqrt(2g) dt

or, on integrating from ho to h, i get

t = sqrt(2/g)[sqrt(h) - sqrt(ho)]A/a

I am not getting the answer, where did i go wrong.