1. The problem statement, all variables and given/known data A cylindrical can of height h and base area A is immersed in water to a depth ho and left to sink down. A small hole of area 'a' exists at the bottom of the base of the can. Determine how quickly the can sinks. http://img80.imageshack.us/my.php?image=fluids1wb7.jpg 2. Relevant equations http://img178.imageshack.us/my.php?image=fluidssolmz5.jpg Thus, vo = sqrt(2gy) AV = avo V: velocity of fluid w.r.t. the container 3. The attempt at a solution Thus, dy/dt = (a/A)sqrt(2gy) or, dy/sqrt(y) = (a/A) sqrt(2g) dt or, on integrating from ho to h, i get t = sqrt(2/g)[sqrt(h) - sqrt(ho)]A/a I am not getting the answer, where did i go wrong.