Hi everyone,(adsbygoogle = window.adsbygoogle || []).push({});

I have a simple problem for you. If we have an isotropic particle density n(r,E) where r is the radius and E the energy in a sphere of radius R, What would be the particle flux over a single side of a detector of area A inside the sphere?

What would it be also if the detector's acceptance would be D?

The first aproach i have tried is that the flux should be around n*V/4pi where n is the particle density and v the mean velocity of the particles and 4pi the total solid angle.The flux over one side of the detector should be 1/2 of the total flux as it is isotropic.

In the case of the acceptance of the detector, simply multiplying the total flux n*v/4pi by the acceptance would be the flux over the detectorÂ´s surface.

Thanx and regards.

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# Homework Help: Flux Calculation

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