Flux In Toroidal Inductor

  • Thread starter jhexp
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  • #1
jhexp
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Homework Statement



A 4.50 mH toroidal inductor has 125 identical equally spaced coils.

4.5 mH = .0045 H (Wb/A)
N = 125
I = 11.5 A
φ = ? - this is what we're finding

If it carries an 11.5 A current, how much magnetic flux passes through each of its coils?

Homework Equations


I'm really blank on this one. I know that the units for the magnetic flux, φ, will be in units Wb. My educated guess is that the equation will be φ = inductance/current.


The Attempt at a Solution



φ = (.0045 H)/(11.5 A) = 3.91*10^-4 Wb
I divided that by 125 and got 3.13*10^-6 Wb
 
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Answers and Replies

  • #2
jhexp
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Ah shi. How dumb of me. Just after posting I realized that I should multiply the inductance by the current and got the correct answer.
 
  • #3
jhexp
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nvm, got it.
 

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