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## Homework Statement

A 4.50 mH toroidal inductor has 125 identical equally spaced coils.

4.5 mH = .0045 H (Wb/A)

N = 125

I = 11.5 A

φ = ? - this is what we're finding

If it carries an 11.5 A current, how much magnetic flux passes through each of its coils?

## Homework Equations

I'm really blank on this one. I know that the units for the magnetic flux, φ, will be in units Wb. My educated guess is that the equation will be φ = inductance/current.

## The Attempt at a Solution

φ = (.0045 H)/(11.5 A) = 3.91*10^-4 Wb

I divided that by 125 and got 3.13*10^-6 Wb