A 4.50 mH toroidal inductor has 125 identical equally spaced coils.
4.5 mH = .0045 H (Wb/A)
N = 125
I = 11.5 A
φ = ? - this is what we're finding
If it carries an 11.5 A current, how much magnetic flux passes through each of its coils?
I'm really blank on this one. I know that the units for the magnetic flux, φ, will be in units Wb. My educated guess is that the equation will be φ = inductance/current.
The Attempt at a Solution
φ = (.0045 H)/(11.5 A) = 3.91*10^-4 Wb
I divided that by 125 and got 3.13*10^-6 Wb