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Flux In Toroidal Inductor

  1. Apr 3, 2010 #1
    1. The problem statement, all variables and given/known data

    A 4.50 mH toroidal inductor has 125 identical equally spaced coils.

    4.5 mH = .0045 H (Wb/A)
    N = 125
    I = 11.5 A
    φ = ? - this is what we're finding

    If it carries an 11.5 A current, how much magnetic flux passes through each of its coils?

    2. Relevant equations
    I'm really blank on this one. I know that the units for the magnetic flux, φ, will be in units Wb. My educated guess is that the equation will be φ = inductance/current.


    3. The attempt at a solution

    φ = (.0045 H)/(11.5 A) = 3.91*10^-4 Wb
    I divided that by 125 and got 3.13*10^-6 Wb
     
  2. jcsd
  3. Apr 3, 2010 #2
    Ah shi. How dumb of me. Just after posting I realized that I should multiply the inductance by the current and got the correct answer.
     
  4. Apr 3, 2010 #3
    nvm, got it.
     
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