1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Flux of the Poynting vector

  1. Jan 16, 2017 #1
    • Moved from technical forums, missing template
    I have some problems in calculating the flux of Poynting's vector through a surface.
    I have that:

    S=c/4π⋅H^2⋅n (S: Poynting's vector, n: versor of the direction of the propagation of the em wave)

    H=1/cR A'
    but: A=(1/cR) d'; A'=(1/cR) d'' ==> H= (1/cR)^2 d''
    ==> S= (c/4π)⋅ 1/(cR)^4 d''^2 n

    I have to find that the result of the flux of S (I don't know through wich surface) is:

    dE/dt=∫S⋅dΩ=...=-2/(3⋅c^3) |d''|^2 (d is magnetic dipole momentum)

    How is it calculated?
    Thanks to everyone who will try to help me.
  2. jcsd
  3. Feb 13, 2017 #2
    Thanks for the thread! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post? The more details the better.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted

Similar Discussions: Flux of the Poynting vector
  1. Poynting vector (Replies: 3)

  2. Poynting vector (Replies: 6)