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Flux through rotating ring

  1. Nov 7, 2011 #1
    1. The problem statement, all variables and given/known data
    A ring can rotate about a horizontal axis(x), and a diameter placed on the x-axis. A uniform field is perpendicular to the ring -B0*y. The diameter of the ring is D. it spins with constant angular velocity ω around the x-axis. At at time t = 0 the ring is entirely in the xy plane

    How do i find the flux change per time? And what does it mean that it can rotate around a diameter.
    I've attached a figure.


    2. Relevant equations
    [itex] Flux = \int \vec{B}\cdot d\vec{a}[/itex]


    3. The attempt at a solution
    At a time t = 0 the flux through the loop is 0 and i tried to write a solution using that B is constant:
    [itex] Flux = B\int sin(\theta (t))d\vec{a}[/itex]
    [itex] Flux/dt = B\int cos(\theta(t) ) \omega d\vec{a}[/itex]
     

    Attached Files:

  2. jcsd
  3. Nov 8, 2011 #2
    Nwm.
    I found out.
     
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