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Fnet and Force.

  • Thread starter t00kool
  • Start date
  • #1
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Homework Statement



An elevator with a mass of 650 Kg supported by steel cable. What is the tension in the calbe when the elevator is accelerated upward at the rate of 3.00 m/s^2


Homework Equations



well he gives the equations that we can use as: Fnet=ma, w=mg and g=9.8m/s^2
I dont know what W means. Also he never taught us how to find tension.


The Attempt at a Solution



Well I used Fnet: 650KG * 3.00m/s^2= ANS.

If this is right can someone explain to me how.


x

Please Help.
 
Last edited:

Answers and Replies

  • #2
rock.freak667
Homework Helper
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The Attempt at a Solution



Well I used Fnet: 650KG * 3.00m/s^2= ANS.

If this is right can someone explain to me how.
well the resultant acceleration is 3 ms[itex]^{-2}[/itex]
so the net force,[itex]F_{net}=650*3=1950N[/itex]

The weight of the elevator is W.
The tension in the cables holding the elevator is T.

If the weight is acting down and tension is acting up, and the resultant of these 2 is in an upward direction. What would be an equation relating the the resultant (net) force, the tension and weight?
 

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