A 250 N force is applied at an angle of 32° above the horizontal to a 96 kg wooden box causing
it to slide along a floor as shown.
The coefficient of friction between the floor and the box is 0.18. What is the magnitude of the net
force on the wooden box?
The Attempt at a Solution
ff=mu times N
ff =0.18 times 9.8 times 96
For normal force would you find the y component ie. 9.8 times 96 times sin32 or do you just do N=W?
and if I do N as the y component "because some of the mass is being lifted" I get the wrong answer too. 122N
it is supposed to be 67N?