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Focal Length of Microscope

  1. Jul 5, 2009 #1
    1. The problem statement, all variables and given/known data

    The near point of a naked eye is 25 cm. When placed at the near point and viewed by the naked eye, a tiny object would have an angular size of 5.2X10-5 rad. When viewed through a compound microscope, however, it has an angular size of -9.20X10-3 rad. (The minus sign indicates that the image produced by the microscope is inverted.) The objective of the microscope has a focal length of 2.8 cm, and the distance between the objective and the eyepiece is 16 cm. Find the focal length of the eyepiece.


    2. Relevant equations
    M=(L-Fe)(N)/FoFe


    3. The attempt at a solution

    Tried using the equation and solved for Fe and got the answer 15.98 but it was wrong. Any Ideas?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jul 6, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    The magnification M = angular size of the image/ angular size of the object. Find M.
    Now M = 25/f(effective), where f(effective) is given by
    1/f(effective) = 1/fo + 1/fe - d/fo*fe
    where fo...>focal length of the objective
    fe...>focal length of the eye-piece
    and d...>distance between objective and eye-piece.
     
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