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For the Graph

  1. Oct 2, 2007 #1
    For the Graph....

    x(t)=1+2cos(pi/3(t+1))

    First i just draw a graph of cos and than... It is just a simple stretch of 1 in the y-direction and a translation of 1 to the left ... correct?
     
  2. jcsd
  3. Oct 2, 2007 #2

    Dick

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    No. Why don't you just start plugging some values of t in and draw the graph? How it's related to cos should then start to become clearer.
     
  4. Oct 2, 2007 #3
    What does the 1 in the beginning of the equation represent dick?
     
  5. Oct 2, 2007 #4

    Dick

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    The 1 is a translation up one unit in x (which you could consider the 'y' direction - depending on how you draw your graph). It's not a 'stretch' and it's not to the left.
     
  6. Oct 2, 2007 #5
    And the Period has the equation 2pi/B...what would the "B" represent in my equation dick? would it be pi/3? .... and how would i calculate what the new zeroes of the graph would be?
     
    Last edited: Oct 2, 2007
  7. Oct 2, 2007 #6

    Dick

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    If you would actually start plotting the graph instead of thinking about doing it this would become apparent. The period would be the increment in t that you need to make pi/3*(t+1) change by 2pi. What might that be? To get the new zeros of your graph solve for x(t)=0.
     
  8. Oct 3, 2007 #7
    thanks alot dick..it also states find all values of t with 0<t<20 such taht x(t)=x(0)...so basically all the values of t in this situtation ...are those values that hit 0 on the x axis ...correct?
     
  9. Oct 3, 2007 #8

    Dick

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    Absolutely.
     
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