For x∈R^n define g:R->R by g(t)=f(tx) g'(t)?

  • Thread starter precondition
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In summary, the function g(t) represents the composition of the original function f(x) with a scaling factor applied to the input vector x. Its domain is all real numbers and its range is all real numbers that can be obtained by applying f(x) to the scaled vector tx. The derivative of g(t) can be found using the chain rule and the input vector x allows for scaling of the original function f(x). Additionally, g(t) can represent any type of function as long as f(x) is defined for the scaled vector tx.
  • #1
precondition
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Have to use chain rule, so I was thinking,
if we let u(t)=tx where x is the vector,
then g(t)=f(u(t)) so dg(t)/dt=d(f u)(t)/dt=(df(t)/dt)u(t)+f(t)(du(t)/dt)
but then I don't know what to do...
 
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  • #2
Please state the problme clearly. Is x a constant vector? What is f?

What you have stated is not the chain rule- it looks more like the product rule. f(u(t)) is not "f u".

dg(t)/dt= (df/du)(du/dt).
 

What does the function g(t) represent?

The function g(t) represents the composition of the original function f(x) with the scaling factor t applied to the input vector x.

What is the domain and range of g(t)?

The domain of g(t) is the set of all real numbers, and the range of g(t) is the set of all real numbers that can be obtained by applying the function f(x) to the scaled vector tx.

What is the derivative of g(t)?

The derivative of g(t) can be found using the chain rule, and is equal to g'(t) = f'(tx)x.

What is the significance of the input vector x in the definition of g(t)?

The input vector x allows for the scaling of the original function f(x), which can help to analyze the behavior of the function at different scales.

Can g(t) be used to represent any type of function?

Yes, g(t) can represent any type of function, as long as the original function f(x) is defined for the scaled vector tx.

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