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Force, acceleration,friction

  1. Aug 4, 2009 #1
    1. The problem statement, all variables and given/known data

    A sled and cargo weighing 490 N is towed by a tractor over a horizontal field where the coefficient of sliding friction is 0.400. If the tractor exerts a force of 300 N, what is the acceleration of the sled?

    2. Relevant equations
    Fk/µkM


    3. The attempt at a solution
    i Tried changing the 490N to Kg by dividing it by 9.81. that gave me 49.95. i then multiplied that by 0.400. then i divided that final number from 300 N.
     
  2. jcsd
  3. Aug 5, 2009 #2

    rl.bhat

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    Homework Helper

    490 N is the normal reaction. So the frictional force fk= μkN.
    Acceleration = (F - fk)/m
     
  4. Aug 5, 2009 #3
    O thank you so much :)
     
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