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**1. Homework Statement**

The small piston of a hydraulic lift has a cross sectional area of (2.8 cm^2), and the large piston connected to it has an area of (17 cm^2). What force of F must be applied to the smaller piston to maintain a load of (28000 N)?

**2. Homework Equations**

A_1 * V_1 = A_2 * V_2

**3. The Attempt at a Solution**

Since the volumes are the same, I set the A * F to be set equal to each other on both sides and solved....but I'm not seeing something in the unit conversion.....Idk what to do.