- #1
jrrodri7
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Homework Statement
The small piston of a hydraulic lift has a cross sectional area of (2.8 cm^2), and the large piston connected to it has an area of (17 cm^2). What force of F must be applied to the smaller piston to maintain a load of (28000 N)?
Homework Equations
A_1 * V_1 = A_2 * V_2
The Attempt at a Solution
Since the volumes are the same, I set the A * F to be set equal to each other on both sides and solved...but I'm not seeing something in the unit conversion...Idk what to do.