1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Force and distance

  1. Sep 17, 2006 #1
    In a grocery store, you push a 13.5 kg shopping cart with a force of 12.5 N. If the cart starts at rest, how far does it move in 3.00 s?

    Here's what I did:
    m=13.5 kg
    f=12.5 N
    V(final)=0+at= 0+(.93)(3)=2.79
    Vf^2=Vi^2+2a(deltax)= solve for change in X= (2a)Vf^2 (Vf = final velocity, Vi= initial velocity)
    so, (2)(.93)*(2.79)^2= 14.5 m.
    Ok, so what did I do wrong? I can't figure it out.....
  2. jcsd
  3. Sep 17, 2006 #2


    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Here's your problem, you've just made a mistake on your manipulation;

    [tex]v_{f}^{2} = v_{i}^{2} + 2ax \Rightarrow x = \frac{v_{f}^{2}}{2a}[/tex]

    Also, becareful of inducing rounding errors.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Force and distance
  1. Force and distance (Replies: 3)