In a grocery store, you push a 13.5 kg shopping cart with a force of 12.5 N. If the cart starts at rest, how far does it move in 3.00 s?(adsbygoogle = window.adsbygoogle || []).push({});

Here's what I did:

m=13.5 kg

f=12.5 N

t=3s

v(i)=0

F=ma

a=f/m

12.5/13.5=0.93m/s^2=accel.

V(final)=0+at= 0+(.93)(3)=2.79

Vf^2=Vi^2+2a(deltax)= solve for change in X= (2a)Vf^2(Vf = final velocity, Vi= initial velocity)

so, (2)(.93)*(2.79)^2= 14.5 m.

Ok, so what did I do wrong? I can't figure it out.....

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# Force and distance

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