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Force And Energy

  1. Jun 4, 2007 #1
    1. The problem statement, all variables and given/known data


    2. The attempt at a solution


    F_x = mg*cos(70)
    =48kg*9.8N/kg*cos (70)
    Is that right
  2. jcsd
  3. Jun 4, 2007 #2
    help me..........................
  4. Jun 4, 2007 #3
    Looks good to me, but don't forget the units, and you need to note the direction of the force as well as the magnitude.
  5. Jun 5, 2007 #4
    F_x = mg*cos(70)
    =48kg*9.8N/kg*cos (70)
    Is that right
  6. Jun 5, 2007 #5
    How can i ind magnitude direction?
  7. Jun 5, 2007 #6
    I think it is along the incline in the direction of displacement.
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