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Force and Impulse

  1. Oct 9, 2008 #1
    1. The problem statement, all variables and given/known data
    The Figure shows an approximate representation of the contact force versus time during the collision of a 66-g tennis ball with a wall. The initial velocity of the ball is 4.375E+1 m/s perpendicular to the wall. What is the speed of the tennis ball after the collision?
    (see attached)

    2. Relevant equations

    3. The attempt at a solution
    Not sure how to start, I know the impulse is the area under the curve, thats all. Thanks

    Attached Files:

  2. jcsd
  3. Oct 9, 2008 #2
    And the impulse is also equal to the change in momentum.
  4. Oct 9, 2008 #3
    Ok, having a real brain fart. What do I need to do with the impulse to get the new velocity?
  5. Oct 9, 2008 #4
    impulse=(final momentum)-(initial momentum)
  6. Oct 9, 2008 #5
    So just divide the Impulse by the mass?
  7. Oct 9, 2008 #6
    If you just divide, you'll get the difference between the two speeds. Is the problem asking for just this?
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