Force and Motion

  • Thread starter dortec
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  • #1
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A 53 kg skier skis directly down a frictionless slope angled at 15° to the horizontal. Choose the positive direction of the x axis to be downhill along the slope. A wind force with component Fx acts on the skier. What is Fx if the magnitude of the skier's velocity is (a) constant, (b) increasing at a rate of 1.5 m/s2, and (c) increasing at a rate of 3.0 m/s.
 

Answers and Replies

  • #2
43
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give us the atempt at the sulution then we can try to help u
 
  • #3
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i did it and got
a: 137.17 n
b: 57.5 n
c: -22n

but im pretty sure they're wrong:P
 
  • #4
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with wich formula

did u do this with the one of potencial energy
 
  • #5
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sigma Fext= M.a newton's second law i think:P .. and u place the forces.. that's how i did it.
 
  • #6
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so u did this with the second law of newton f=m x a
 
  • #7
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yes|-) .. now can someone help me please^o)?
 
  • #8
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There are two forces, the force of the wind and his weight (only in the c-direction, down the ramp).

a) Constant velocity means that there is no acceleration and the net force is zero.

b/c) He is accelerating down the hill which means that there is a net force.

Draw an fbd then you can create an equation for a/b/c based on the parameters.
 
  • #9
43
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u did just the forces but how about the angel thats ur failur a
 
  • #10
43
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There are two forces, the force of the wind and his weight.

a) Constant velocity means that there is no acceleration and the net force is zero.

b/c) He is accelerating down the hill which means that there is a net force.

Draw an fbd then you can create an equation for a/b/c based on the parameters.
nah he did that with the f=ma parameters but u need to put the angel so if it is like u say it will go like this f=ma=53kg x o m/s2 and then he would have o N and u would do 2 and 3 like this
 

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