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- Thread starter Kp0684
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- #2

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I would use one of the kinematic equations to find the acceleration and then multiple that by the mass of the torso myself.

Edit:Should probably post questions like these in the homework section.

Edit:Should probably post questions like these in the homework section.

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- #3

Doc Al

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14.7m/s is the car's initialKp0684 said:i get 14.7m/s2 for the cars speed which is my (a),

(I am moving this to the Homework forum, where it belongs.)

- #4

xanthym

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However, it's also true the original kinetic energy E=(1/2)(41 kg)(14.7 m/s)^2 was dissipated to 0 over 0.65 meters by the assumed constant force F=(E/0.65).Kp0684 said:

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- #5

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i have the magnitude force equal to (6.82 x 10^3 N).........

- #6

xanthym

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Your answer F=(6.82x10^3 N) is CORRECT.

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