1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Force and Static friction

  1. Oct 22, 2012 #1
    1. The problem statement, all variables and given/known data
    A small crane is lifting a 10kg box of nails. If the coefficient of static friction is .4, calculate the angle at which the box begins to slide.


    2. Relevant equations
    Fg x component: mg sin
    Ff = ukmgcos


    3. The attempt at a solution
    Fnet = Fgx - Ff
    Would the net force be zero since there's no acceleration in its static state?
    Do I then rearrange the equation to solve for the angle?
     
  2. jcsd
  3. Oct 22, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi Nicolaus! :wink:
    (I don't understand the actual question, but …)

    That's correct: for static friction, the acceleration is zero, and so the net force is zero.

    And yes, rearrange and solve for the angle :smile:
     
  4. Oct 22, 2012 #3
    Ok, would it then make sense that the result ends up being just the inverse of tan multiplied by 0.4 (which is the coefficient of the static friction): angle = tan(inverse) x .4
     
  5. Oct 22, 2012 #4

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    erm :redface:

    i've already said i don't understand the question :confused:
     
  6. Oct 22, 2012 #5
    Is it the way it was worded or..? Imagine the box was on a flat board and you slowly start to tilt the board.

    EDIT: I think I did this wrong. I'm supposed to calculate the Force of static friction on the flat surface to find the minimum force required for it to move then place that value into the equation (ignoring the cos angle).
    Can someone correct me on this.
     
    Last edited: Oct 22, 2012
  7. Oct 22, 2012 #6

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    ah, in that case, the crane isn't lifting the box, it's lifting the board :wink:

    and yes, tan-1µk would be correct :smile:
    oooh, lost me again :cry:
     
  8. Oct 22, 2012 #7
    Yes, forgot to state that the box was on a plank. Ignore my EDIT. So, if there were 2 boxes (each of different mass) with that same coefficient of static friction, would the angles at which each box starts to slide be the same?
    Thanks :)
     
  9. Oct 22, 2012 #8

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    yes, mass and shape would make no difference :smile:

    (btw, what have the nails to do with it? :confused:

    is there a second part in which you're asked whether the box tips over?)
     
  10. Oct 22, 2012 #9
    No, nothing. It's just a problem using a construction site and 2 boxes of nails as the setting and objects, respectively. It says that there are 2 boxes (each of different mass) on a plank being raised by a crane and the static friction is .4, and asks us to find the angle at which each box starts to slide. We concluded that both would, logically, start to slide at the same angle since the the mass and gravitational constant cancel out in both cases when solving for the angle.
    :)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Force and Static friction
Loading...