1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Force Applied

  1. Jun 2, 2012 #1
    1. The problem statement, all variables and given/known data

    What Force must be applied to a steel bar, 1in [25.4mm] square and 2ft [610mm] long, to produce an elongation of .016in. [.4064mm]?

    2. Relevant equations

    L=610mm
    ΔL=.4064mm
    E=29,000,000


    3. The attempt at a solution

    What I know is:

    E=Stress/Strain

    Strain=.4064/610 = 6.66*10^-4

    Stress=F/A
    Stress=19329.65
     
  2. jcsd
  3. Jun 2, 2012 #2
    I am not getting the correct answer for FORCE. F=stress(Area) Am I messing up the Area some how?? The answer is suppose to be 86KN of Force or 19,333lb
     
  4. Jun 2, 2012 #3
    Hi raiderUM. What are the units for Young's modulus that you are using. From your numerical answers you're using SI units. But, E=29x106 is small for steel, it should be about 103 to 104 times as large as that number. This would give you the same approximately the same error from what you had.
     
  5. Jun 2, 2012 #4
    The units of the Young's modulus that the OP used were psi. He already has the right answer (aside from roundoff).

    Chet
     
  6. Jun 2, 2012 #5
    Ok, that's the reason. You need to convert it into Pa or Nm-2. On wikipedia it says that for steel [itex]E=200\times10^9 Nm^{-2}[/itex]. This will give you the answer that you need.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Force Applied
  1. Applied Forces (Replies: 3)

  2. Applied Force (Replies: 6)

  3. Force applied (Replies: 1)

  4. Forces applying (Replies: 1)

  5. Applied force (Replies: 2)

Loading...