A ballon which has weight 10.8 kN fall down with acceleration 1 m/s². What mass we have to pull of from ballon to make it(ballon) rise up with same acceleration.
P = m×g
P = m(g ± a)
P = 10.8 kN = 10.8×10³ N
a = 1 m/s²
g = 10 m/s²
m₀ - ? (but answer is in Newtons, so we have to find weight `P`)
The Attempt at a Solution
The first we have to find ballon mass using weight:
P = m(g-a)
m = P / (g-a) => m = 1200 kg;
Write first Newtons law (Y axis show down):
Y: ma = mg - F
We have to find that `F`
F = -m(a-g) => F = -1200*(1-10) = 10800 N.
Fail! F = P, and it's impossible. In this case ballon should be static without any movement.
Anyway, my next idea is:
-ma = (m - m₀)×g - F
-ma *— because acceleration should change the direction to opposite (up)
We can't edit `F` but we can change mass.
With calculations I got:
m₀ = (F-ma) / g + m