(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Force at an Incline

A 3.54 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=11.90 N at an angle theta=16.0o above the horizontal, as shown. What is the speed of the block 6.10 seconds after it starts moving?

Fgravity = (3.54*9.8) = 34.7N

F/m = a .... 11.90/3.54 = 3.36 m/s^2

How would I calculate the horizontal force?

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# Homework Help: Force at an Incline

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