1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Force diagrams, Quick Question

  1. Sep 19, 2007 #1
    1. The problem statement, all variables and given/known data
    [​IMG]

    I understood every except, How do they get the 9 degrees in part c?

    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Sep 19, 2007 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Look at the components of the resultant of the three forces: using an inverse tangent you should be able to find the angle it makes with the x axis. (Draw a right triangle.)
     
  4. Sep 19, 2007 #3
    So then is arctan(30/190) 9 degrees?

    (I don't have access to a radian calculator right now), also how do they get the 19N?
     
  5. Sep 19, 2007 #4

    Doc Al

    User Avatar

    Staff: Mentor

    Yes.
    You don't need a radian calculator. (If ever you don't have a calculator handy, Google has one.)

    The 19 N makes no sense. But the components are close enough, so you should be able to figure the magnitude properly from that.
     
  6. Sep 19, 2007 #5
    So the real F is sqrt(130^2+30^2) am I correct?
     
  7. Sep 19, 2007 #6

    Doc Al

    User Avatar

    Staff: Mentor

    Where did the 130 come from?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Force diagrams, Quick Question
Loading...