Force due to a submersible water pump to move an underwater vehicle

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SUMMARY

The discussion focuses on calculating the force exerted by a 500 GPH submersible bilge pump for a university-designed underwater vehicle. The user attempts to convert the flow rate into force using pressure equations, specifically Pressure = Density * Gravity * Height and Pressure = Force / Area. Key variables include water density (1000 kg/m³) and gravitational acceleration (9.8 m/s²). The user concludes that additional information, such as the velocity of water exiting the pump and the area of the nozzle, is necessary to accurately determine the force in Newtons.

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  • Understanding of fluid dynamics principles
  • Knowledge of pressure equations in physics
  • Familiarity with unit conversions, specifically between flow rates and force
  • Basic concepts of thrust in fluid mechanics
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  • Explore "Bernoulli's principle" and its application to pumps
  • Investigate "nozzle design and its effect on flow rate" for pumps
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Engineering students, mechanical engineers, and hobbyists designing underwater vehicles or working with submersible pumps.

DrewMan776
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Homework Statement


I'm trying to find the force exerted by a 500 GPH (gallons per hour) submersible bilge pump.

My team is designing a submersible vehicle for our university course. The vehicle is only supposed to move up and down in the vertical direction; basically it should just be able to change its depth. We're using submersible bilge pumps to move the vehicle. I'm designing the control system using an embedded microprocessor and I'm trying to understand the force exerted by the pump to correctly design the control logic.

The spec for the pump is just gallons per hour, and I think there should be a way, using pressure, water density etc, to convert this to a force in Newtons, but I can't quite get there.

Homework Equations



Pressure = Density * Gravity * Height
Pressure = Force / Area
Density = Mass / Volume

The Attempt at a Solution


I first tried a dimensional analysis to get Gallons per hour into Newtons, but it isn't quite that simple:

1 N = 1 kg * m / s^2
1 Gallon / hour = 1.05 * 10^-6 [m^3 / s]
Density of water = 1000 kg/m3

I don't think there is a way to manipulate the units to obtain Newtons. I don't think that Gallons per hour is in fact a force, but a flow rate, so we need more information.

Then I tried using the equation for pressure:
Assuming the water pump is facing up, and the vehicle is 10 m under the surface of the water tank, then I think that the pressure on the pump is:

Pressure acting on the pump = pgh = (1000 kg / m^3) * (9.8 m/s^2) * 10 m

Then, to move the vehicle, the pump must exert a force:

F = Pressure acting on the pump / Area of pump nozzle

But this doesn't take into account the 500 GPH rating of the pump, so we still need more information.

I don't particularly want to include hydrodynamics in this simple model because it would definitely complicate things.

I think the pieces are there, I just can't make them fit.

Any help would be greatly appreciated.
 
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You'll want to look at the velocity of the water as it leaves the pump's outlet. This will be affected by the ambient pressure to some extent (maybe not significantly: it depends upon the depth of the tank and the capabilities of the pump; some pumps will deliver a given volumetric rate of water against a wide range of pressure conditions). It will certainly depend upon the diameter of the outlet nozzle.

Next investigate "thrust", as in rocket thrust.
 

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